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11x^2+9x=1.080
We move all terms to the left:
11x^2+9x-(1.080)=0
We add all the numbers together, and all the variables
11x^2+9x-(1.08)=0
We add all the numbers together, and all the variables
11x^2+9x-1.08=0
a = 11; b = 9; c = -1.08;
Δ = b2-4ac
Δ = 92-4·11·(-1.08)
Δ = 128.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{128.52}}{2*11}=\frac{-9-\sqrt{128.52}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{128.52}}{2*11}=\frac{-9+\sqrt{128.52}}{22} $
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